基于jquery实现控制经纬度显示地图与卫星

  技术百科     |      2026-01-17 18:57
复制代码 代码如下:
<link href="css/jquery.ui.base.css" rel="stylesheet" type="text/css" />
<link href="css/jquery.ui.theme.css" rel="stylesheet" type="text/css" />
<script src="http://maps.google.com/maps/api/js?sensor=false" type="text/javascript"></script>
<script src="js/jquery-1.9.1.js" type="text/javascript"></script>
<script src="js/jquery.mousewheel.js" type="text/javascript"></script>
<script src="js/jquery.ui.core.js" type="text/javascript"></script>
<script src="js/jquery.ui.widget.js" type="text/javascript"></script>
<script src="js/jquery.ui.button.js" type="text/javascript"></script>
<script src="js/jquery.ui.spinner.js" type="text/javascript"></script>
<link href="css/demos.css" rel="stylesheet" type="text/css" />
<script type="text/javascript">
$(function () {
function latlong() {
return new google.maps.LatLng($("#lat").val(), $("#lng").val());
}
function position() {
map.setCenter(latlong());
}
$("#lat, #lng").spinner({
step: .001,
change: position,
stop: position
});
var map = new google.maps.Map($("#map")[0], {
zoom: 8,
center: latlong(),
mapTypeId: google.maps.MapTypeId.ROADMAP
});
});
</script>
<style type="text/css">
#map {
width:500px;
height:500px;
}
</style>
</head>
<body>
<label for="lat">纬度</label>
<input id="lat" name="lat" value="44.797"/>
<br>
<label for="lng">经度</label>
<input id="lng" name="lng" value="-93.278"/>
<div id="map"></div>
<div class="demo-description">
</div>